2(6x+4)-62x=3(4x+3)+1

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Solution for 2(6x+4)-62x=3(4x+3)+1 equation: 



2(6x+4)-62x=3(4x+3)+1

We move all terms to the left:

2(6x+4)-62x-(3(4x+3)+1)=0

We add all the numbers together, and all the variables

-62x+2(6x+4)-(3(4x+3)+1)=0

We multiply parentheses

-62x+12x-(3(4x+3)+1)+8=0



We calculate terms in parentheses: -(3(4x+3)+1), so:

3(4x+3)+1

We multiply parentheses

12x+9+1

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

-50x-(12x+10)+8=0

We get rid of parentheses

-50x-12x-10+8=0

We add all the numbers together, and all the variables

-62x-2=0

We move all terms containing x to the left, all other terms to the right

-62x=2

x=2/-62

x=-1/31

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