8(n+1)+6(n-3)=7n+2n

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Solution for 8(n+1)+6(n-3)=7n+2n equation: 



8(n+1)+6(n-3)=7n+2n

We move all terms to the left:

8(n+1)+6(n-3)-(7n+2n)=0

We add all the numbers together, and all the variables

8(n+1)+6(n-3)-(+9n)=0

We multiply parentheses

8n+6n-(+9n)+8-18=0

We get rid of parentheses

8n+6n-9n+8-18=0

We add all the numbers together, and all the variables

5n-10=0

We move all terms containing n to the left, all other terms to the right

5n=10

n=10/5

n=2

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