8r-6(1+2r)=-3(r-3)

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Solution for 8r-6(1+2r)=-3(r-3) equation: 



8r-6(1+2r)=-3(r-3)

We move all terms to the left:

8r-6(1+2r)-(-3(r-3))=0

We add all the numbers together, and all the variables

8r-6(2r+1)-(-3(r-3))=0

We multiply parentheses

8r-12r-(-3(r-3))-6=0



We calculate terms in parentheses: -(-3(r-3)), so:

-3(r-3)

We multiply parentheses

-3r+9

Back to the equation:

-(-3r+9)



We add all the numbers together, and all the variables

-4r-(-3r+9)-6=0

We get rid of parentheses

-4r+3r-9-6=0

We add all the numbers together, and all the variables

-1r-15=0

We move all terms containing r to the left, all other terms to the right

-r=15

r=15/-1

r=-15

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