3/4g-9=(g+1)

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Solution for 3/4g-9=(g+1) equation: 



3/4g-9=(g+1)

We move all terms to the left:

3/4g-9-((g+1))=0



Domain of the equation: 4g!=0

g!=0/4

g!=0

g∈R



We multiply all the terms by the denominator


-(((g+1)))*4g-9*4g+3=0

Wy multiply elements

-(((g+1)))*4g-36g+3=0

We add all the numbers together, and all the variables

-36g-(((g+1)))*4g+3=0

We move all terms containing g to the left, all other terms to the right

-36g-(((g+1)))*4g=-3

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