2(3-(4+2x))-28x=-26+4(6-8x)

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Solution for 2(3-(4+2x))-28x=-26+4(6-8x) equation: 



2(3-(4+2x))-28x=-26+4(6-8x)

We move all terms to the left:

2(3-(4+2x))-28x-(-26+4(6-8x))=0

We add all the numbers together, and all the variables

2(3-(2x+4))-28x-(-26+4(-8x+6))=0

We add all the numbers together, and all the variables

-28x+2(3-(2x+4))-(-26+4(-8x+6))=0



We calculate terms in parentheses: -(-26+4(-8x+6)), so:

-26+4(-8x+6)

determiningTheFunctionDomain
4(-8x+6)-26

We multiply parentheses

-32x+24-26

We add all the numbers together, and all the variables

-32x-2

Back to the equation:

-(-32x-2)



We get rid of parentheses

-28x+2(3-(2x+4))+32x+2=0

We add all the numbers together, and all the variables

4x+2(3-(2x+4))+2=0

We move all terms containing x to the left, all other terms to the right

4x+2(3-(2x+4))=-2

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