12=8(1/2z-2)

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Solution for 12=8(1/2z-2) equation: 



12=8(1/2z-2)

We move all terms to the left:

12-(8(1/2z-2))=0



Domain of the equation: 2z-2))!=0

z∈R



We multiply all the terms by the denominator


-(8(1+12*2z-2))=0



We calculate terms in parentheses: -(8(1+12*2z-2)), so:

8(1+12*2z-2)

We add all the numbers together, and all the variables

8(12*2z-1)

We multiply parentheses

192z-8

Back to the equation:

-(192z-8)



We get rid of parentheses

-192z+8=0

We move all terms containing z to the left, all other terms to the right

-192z=-8

z=-8/-192

z=1/24

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