8(3x+3)-((x+3)+(x+2))=0

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Solution for 8(3x+3)-((x+3)+(x+2))=0 equation: 



8(3x+3)-((x+3)+(x+2))=0

We multiply parentheses

24x-((x+3)+(x+2))+24=0



We calculate terms in parentheses: -((x+3)+(x+2)), so:

(x+3)+(x+2)

We get rid of parentheses

x+x+3+2

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

24x-2x-5+24=0

We add all the numbers together, and all the variables

22x+19=0

We move all terms containing x to the left, all other terms to the right

22x=-19

x=-19/22

x=-19/22

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