5(y+2)-(y-1)=3

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Solution for 5(y+2)-(y-1)=3 equation: 



5(y+2)-(y-1)=3

We move all terms to the left:

5(y+2)-(y-1)-(3)=0

We multiply parentheses

5y-(y-1)+10-3=0

We get rid of parentheses

5y-y+1+10-3=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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