128=8(1-3b)

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Solution for 128=8(1-3b) equation: 



128=8(1-3b)

We move all terms to the left:

128-(8(1-3b))=0

We add all the numbers together, and all the variables

-(8(-3b+1))+128=0



We calculate terms in parentheses: -(8(-3b+1)), so:

8(-3b+1)

We multiply parentheses

-24b+8

Back to the equation:

-(-24b+8)



We get rid of parentheses

24b-8+128=0

We add all the numbers together, and all the variables

24b+120=0

We move all terms containing b to the left, all other terms to the right

24b=-120

b=-120/24

b=-5

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