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X2+3X-504=0
We add all the numbers together, and all the variables
X^2+3X-504=0
a = 1; b = 3; c = -504;
Δ = b2-4ac
Δ = 32-4·1·(-504)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-45}{2*1}=\frac{-48}{2} =-24 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+45}{2*1}=\frac{42}{2} =21 $
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