6(y+3)=-2(5y-2)+8y

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Solution for 6(y+3)=-2(5y-2)+8y equation: 



6(y+3)=-2(5y-2)+8y

We move all terms to the left:

6(y+3)-(-2(5y-2)+8y)=0

We multiply parentheses

6y-(-2(5y-2)+8y)+18=0



We calculate terms in parentheses: -(-2(5y-2)+8y), so:

-2(5y-2)+8y

We add all the numbers together, and all the variables

8y-2(5y-2)

We multiply parentheses

8y-10y+4

We add all the numbers together, and all the variables

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

6y+2y-4+18=0

We add all the numbers together, and all the variables

8y+14=0

We move all terms containing y to the left, all other terms to the right

8y=-14

y=-14/8

y=-1+3/4

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