21p-5(3-5p)=2(p-6)-11

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Solution for 21p-5(3-5p)=2(p-6)-11 equation: 



21p-5(3-5p)=2(p-6)-11

We move all terms to the left:

21p-5(3-5p)-(2(p-6)-11)=0

We add all the numbers together, and all the variables

21p-5(-5p+3)-(2(p-6)-11)=0

We multiply parentheses

21p+25p-(2(p-6)-11)-15=0



We calculate terms in parentheses: -(2(p-6)-11), so:

2(p-6)-11

We multiply parentheses

2p-12-11

We add all the numbers together, and all the variables

2p-23

Back to the equation:

-(2p-23)



We add all the numbers together, and all the variables

46p-(2p-23)-15=0

We get rid of parentheses

46p-2p+23-15=0

We add all the numbers together, and all the variables

44p+8=0

We move all terms containing p to the left, all other terms to the right

44p=-8

p=-8/44

p=-2/11

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