4(2-3x)=2(3x-4)+6x

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Solution for 4(2-3x)=2(3x-4)+6x equation: 



4(2-3x)=2(3x-4)+6x

We move all terms to the left:

4(2-3x)-(2(3x-4)+6x)=0

We add all the numbers together, and all the variables

4(-3x+2)-(2(3x-4)+6x)=0

We multiply parentheses

-12x-(2(3x-4)+6x)+8=0



We calculate terms in parentheses: -(2(3x-4)+6x), so:

2(3x-4)+6x

We add all the numbers together, and all the variables

6x+2(3x-4)

We multiply parentheses

6x+6x-8

We add all the numbers together, and all the variables

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

-12x-12x+8+8=0

We add all the numbers together, and all the variables

-24x+16=0

We move all terms containing x to the left, all other terms to the right

-24x=-16

x=-16/-24

x=2/3

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