128=16+(4x/13)

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Solution for 128=16+(4x/13) equation: 



128=16+(4x/13)

We move all terms to the left:

128-(16+(4x/13))=0

We add all the numbers together, and all the variables

-(16+(+4x/13))+128=0

We multiply all the terms by the denominator


-(16+(+4x+128*13))=0



We calculate terms in parentheses: -(16+(+4x+128*13)), so:

16+(+4x+128*13)

determiningTheFunctionDomain
(+4x+128*13)+16

We add all the numbers together, and all the variables

(4x+1664)+16

We get rid of parentheses

4x+1664+16

We add all the numbers together, and all the variables

4x+1680

Back to the equation:

-(4x+1680)



We get rid of parentheses

-4x-1680=0

We move all terms containing x to the left, all other terms to the right

-4x=1680

x=1680/-4

x=-420

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