6x-3+3(2x+3)=-3(x+4)

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Solution for 6x-3+3(2x+3)=-3(x+4) equation: 



6x-3+3(2x+3)=-3(x+4)

We move all terms to the left:

6x-3+3(2x+3)-(-3(x+4))=0

We multiply parentheses

6x+6x-(-3(x+4))+9-3=0



We calculate terms in parentheses: -(-3(x+4)), so:

-3(x+4)

We multiply parentheses

-3x-12

Back to the equation:

-(-3x-12)



We add all the numbers together, and all the variables

12x-(-3x-12)+6=0

We get rid of parentheses

12x+3x+12+6=0

We add all the numbers together, and all the variables

15x+18=0

We move all terms containing x to the left, all other terms to the right

15x=-18

x=-18/15

x=-1+1/5

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