6(-18+3y)=3(-6y-12)

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Solution for 6(-18+3y)=3(-6y-12) equation: 



6(-18+3y)=3(-6y-12)

We move all terms to the left:

6(-18+3y)-(3(-6y-12))=0

We add all the numbers together, and all the variables

6(3y-18)-(3(-6y-12))=0

We multiply parentheses

18y-(3(-6y-12))-108=0



We calculate terms in parentheses: -(3(-6y-12)), so:

3(-6y-12)

We multiply parentheses

-18y-36

Back to the equation:

-(-18y-36)



We get rid of parentheses

18y+18y+36-108=0

We add all the numbers together, and all the variables

36y-72=0

We move all terms containing y to the left, all other terms to the right

36y=72

y=72/36

y=2

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