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((2x-5)/3)=11
We move all terms to the left:
((2x-5)/3)-(11)=0
We multiply all the terms by the denominator
((2x-5)-11*3)=0
We calculate terms in parentheses: +((2x-5)-11*3), so:We get rid of parentheses
(2x-5)-11*3
We add all the numbers together, and all the variables
(2x-5)-33
We get rid of parentheses
2x-5-33
We add all the numbers together, and all the variables
2x-38
Back to the equation:
+(2x-38)
2x-38=0
We move all terms containing x to the left, all other terms to the right
2x=38
x=38/2
x=19
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