2(n-8)+4n=-2+2(-10-3n)

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Solution for 2(n-8)+4n=-2+2(-10-3n) equation: 



2(n-8)+4n=-2+2(-10-3n)

We move all terms to the left:

2(n-8)+4n-(-2+2(-10-3n))=0

We add all the numbers together, and all the variables

2(n-8)+4n-(-2+2(-3n-10))=0

We add all the numbers together, and all the variables

4n+2(n-8)-(-2+2(-3n-10))=0

We multiply parentheses

4n+2n-(-2+2(-3n-10))-16=0



We calculate terms in parentheses: -(-2+2(-3n-10)), so:

-2+2(-3n-10)

determiningTheFunctionDomain
2(-3n-10)-2

We multiply parentheses

-6n-20-2

We add all the numbers together, and all the variables

-6n-22

Back to the equation:

-(-6n-22)



We add all the numbers together, and all the variables

6n-(-6n-22)-16=0

We get rid of parentheses

6n+6n+22-16=0

We add all the numbers together, and all the variables

12n+6=0

We move all terms containing n to the left, all other terms to the right

12n=-6

n=-6/12

n=-1/2

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