10(x+4)=8-(x+2)

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Solution for 10(x+4)=8-(x+2) equation: 



10(x+4)=8-(x+2)

We move all terms to the left:

10(x+4)-(8-(x+2))=0

We multiply parentheses

10x-(8-(x+2))+40=0



We calculate terms in parentheses: -(8-(x+2)), so:

8-(x+2)

determiningTheFunctionDomain
-(x+2)+8

We get rid of parentheses

-x-2+8

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We get rid of parentheses

10x+1x-6+40=0

We add all the numbers together, and all the variables

11x+34=0

We move all terms containing x to the left, all other terms to the right

11x=-34

x=-34/11

x=-3+1/11

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