If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+38x+48=0
a = 5; b = 38; c = +48;
Δ = b2-4ac
Δ = 382-4·5·48
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-22}{2*5}=\frac{-60}{10} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+22}{2*5}=\frac{-16}{10} =-1+3/5 $
| 5x²+38x+48=0 | | 7-(4p+3)=6(5p-3)-(p-7) | | 12−5/1r=2r+1 | | 8y+3=5y-18 | | 2(2y+1)=3(y-2)+11 | | 3(2n+2)=5(n-1)+9 | | 3(2n=2)=5(n-1)+9 | | 7(n+1)-2=6n+6 | | 0.8n=-40 | | 3x-2=175 | | 6r7+6r6=9r5+9r4 | | 1.25x-60=1160 | | -2(3x+2)-4(1-x)=2(4x+2)-6 | | 4x+x-3=7x-5+7 | | 1.25x-60=2320 | | -3y+2(2y+1)=3(4y-2)-3 | | 2(3+x)=4(4x-1)-18 | | -3(2y+3)-17=-4(y+8)2y | | 12q+1=12 | | 4(2y+1)-2=-4 | | 112q+1=12 | | 1/14(n-2)=2/7(n+9)-1/7n | | -1/3-5y=9 | | 9u-30=15u-6 | | 12(q+1)=12 | | 3q+36=12 | | 2+10h=7h+2 | | 12b+5=17 | | -6y+3=-5y | | -6h-9=-13-4h | | 3x+5/4=4x+5/4 | | 4y-26=12+3y |