2(3+x)=4(4x-1)-18

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Solution for 2(3+x)=4(4x-1)-18 equation: 



2(3+x)=4(4x-1)-18

We move all terms to the left:

2(3+x)-(4(4x-1)-18)=0

We add all the numbers together, and all the variables

2(x+3)-(4(4x-1)-18)=0

We multiply parentheses

2x-(4(4x-1)-18)+6=0



We calculate terms in parentheses: -(4(4x-1)-18), so:

4(4x-1)-18

We multiply parentheses

16x-4-18

We add all the numbers together, and all the variables

16x-22

Back to the equation:

-(16x-22)



We get rid of parentheses

2x-16x+22+6=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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