8x+2(x-4)=5(x+1)-4

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Solution for 8x+2(x-4)=5(x+1)-4 equation: 



8x+2(x-4)=5(x+1)-4

We move all terms to the left:

8x+2(x-4)-(5(x+1)-4)=0

We multiply parentheses

8x+2x-(5(x+1)-4)-8=0



We calculate terms in parentheses: -(5(x+1)-4), so:

5(x+1)-4

We multiply parentheses

5x+5-4

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We add all the numbers together, and all the variables

10x-(5x+1)-8=0

We get rid of parentheses

10x-5x-1-8=0

We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5

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