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x=7/8(x)+4
We move all terms to the left:
x-(7/8(x)+4)=0
Domain of the equation: 8x+4)!=0We get rid of parentheses
x∈R
x-7/8x-4=0
We multiply all the terms by the denominator
x*8x-4*8x-7=0
Wy multiply elements
8x^2-32x-7=0
a = 8; b = -32; c = -7;
Δ = b2-4ac
Δ = -322-4·8·(-7)
Δ = 1248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1248}=\sqrt{16*78}=\sqrt{16}*\sqrt{78}=4\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{78}}{2*8}=\frac{32-4\sqrt{78}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{78}}{2*8}=\frac{32+4\sqrt{78}}{16} $
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