2(2y+1)=3(y-2)+11

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Solution for 2(2y+1)=3(y-2)+11 equation: 



2(2y+1)=3(y-2)+11

We move all terms to the left:

2(2y+1)-(3(y-2)+11)=0

We multiply parentheses

4y-(3(y-2)+11)+2=0



We calculate terms in parentheses: -(3(y-2)+11), so:

3(y-2)+11

We multiply parentheses

3y-6+11

We add all the numbers together, and all the variables

3y+5

Back to the equation:

-(3y+5)



We get rid of parentheses

4y-3y-5+2=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3

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