-2(3x+2)-4(1-x)=2(4x+2)-6

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Solution for -2(3x+2)-4(1-x)=2(4x+2)-6 equation: 



-2(3x+2)-4(1-x)=2(4x+2)-6

We move all terms to the left:

-2(3x+2)-4(1-x)-(2(4x+2)-6)=0

We add all the numbers together, and all the variables

-2(3x+2)-4(-1x+1)-(2(4x+2)-6)=0

We multiply parentheses

-6x+4x-(2(4x+2)-6)-4-4=0



We calculate terms in parentheses: -(2(4x+2)-6), so:

2(4x+2)-6

We multiply parentheses

8x+4-6

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We add all the numbers together, and all the variables

-2x-(8x-2)-8=0

We get rid of parentheses

-2x-8x+2-8=0

We add all the numbers together, and all the variables

-10x-6=0

We move all terms containing x to the left, all other terms to the right

-10x=6

x=6/-10

x=-3/5

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