5c(49c+3c)=456c

Solution for 5c(49c+3c)=456c equation:

5c(49c+3c)=456c

We move all terms to the left:

5c(49c+3c)-(456c)=0

We add all the numbers together, and all the variables

5c(+52c)-456c=0

We add all the numbers together, and all the variables

-456c+5c(+52c)=0

We multiply parentheses

260c^2-456c=0

a = 260; b = -456; c = 0;
Δ = b2-4ac
Δ = -4562-4·260·0
Δ = 207936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{207936}=456$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-456)-456}{2*260}=\frac{0}{520}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-456)+456}{2*260}=\frac{912}{520}
=1+49/65
$