11b+4(3b+7)=5(b+12)

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Solution for 11b+4(3b+7)=5(b+12) equation: 



11b+4(3b+7)=5(b+12)

We move all terms to the left:

11b+4(3b+7)-(5(b+12))=0

We multiply parentheses

11b+12b-(5(b+12))+28=0



We calculate terms in parentheses: -(5(b+12)), so:

5(b+12)

We multiply parentheses

5b+60

Back to the equation:

-(5b+60)



We add all the numbers together, and all the variables

23b-(5b+60)+28=0

We get rid of parentheses

23b-5b-60+28=0

We add all the numbers together, and all the variables

18b-32=0

We move all terms containing b to the left, all other terms to the right

18b=32

b=32/18

b=1+7/9

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