f(2+1)=-2f(2)+8

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Solution for f(2+1)=-2f(2)+8 equation: 



f(2+1)=-2f(2)+8

We move all terms to the left:

f(2+1)-(-2f(2)+8)=0

We add all the numbers together, and all the variables

-(-2f^2+8)+f3=0

We add all the numbers together, and all the variables

f^3-(-2f^2+8)=0

We get rid of parentheses

f^3+2f^2-8=0

We do not support efpression: f^3

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