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(2x-1)(-4x-3)=4
We move all terms to the left:
(2x-1)(-4x-3)-(4)=0
We multiply parentheses ..
(-8x^2-6x+4x+3)-4=0
We get rid of parentheses
-8x^2-6x+4x+3-4=0
We add all the numbers together, and all the variables
-8x^2-2x-1=0
a = -8; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-8)·(-1)
Δ = -28
Delta is less than zero, so there is no solution for the equation
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