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(2x-1)(-4x-3)=0
We multiply parentheses ..
(-8x^2-6x+4x+3)=0
We get rid of parentheses
-8x^2-6x+4x+3=0
We add all the numbers together, and all the variables
-8x^2-2x+3=0
a = -8; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-8)·3
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-8}=\frac{-8}{-16} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-8}=\frac{12}{-16} =-3/4 $
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