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50=300/x2
We move all terms to the left:
50-(300/x2)=0
Domain of the equation: x2)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+300/x2)+50=0
We get rid of parentheses
-300/x2+50=0
We multiply all the terms by the denominator
50*x2-300=0
We add all the numbers together, and all the variables
50x^2-300=0
a = 50; b = 0; c = -300;
Δ = b2-4ac
Δ = 02-4·50·(-300)
Δ = 60000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{60000}=\sqrt{10000*6}=\sqrt{10000}*\sqrt{6}=100\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100\sqrt{6}}{2*50}=\frac{0-100\sqrt{6}}{100} =-\frac{100\sqrt{6}}{100} =-\sqrt{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100\sqrt{6}}{2*50}=\frac{0+100\sqrt{6}}{100} =\frac{100\sqrt{6}}{100} =\sqrt{6} $
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