3x(3x-4x)=15+45

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Solution for 3x(3x-4x)=15+45 equation: 



3x(3x-4x)=15+45

We move all terms to the left:

3x(3x-4x)-(15+45)=0

We add all the numbers together, and all the variables

3x(-1x)-60=0

We multiply parentheses

-3x^2-60=0

a = -3; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·(-3)·(-60)
Δ = -720
Delta is less than zero, so there is no solution for the equation

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