24(3-k/2)=8k+72(k+1)

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Solution for 24(3-k/2)=8k+72(k+1) equation: 



24(3-k/2)=8k+72(k+1)

We move all terms to the left:

24(3-k/2)-(8k+72(k+1))=0

We add all the numbers together, and all the variables

24(-k/2+3)-(8k+72(k+1))=0

We multiply parentheses

-24k-(8k+72(k+1))+72=0



We calculate terms in parentheses: -(8k+72(k+1)), so:

8k+72(k+1)

We multiply parentheses

8k+72k+72

We add all the numbers together, and all the variables

80k+72

Back to the equation:

-(80k+72)



We get rid of parentheses

-24k-80k-72+72=0

We add all the numbers together, and all the variables

-104k=0

k=0/-104

k=0

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