2(27-x)=100-4x+6(3-x)

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Solution for 2(27-x)=100-4x+6(3-x) equation: 



2(27-x)=100-4x+6(3-x)

We move all terms to the left:

2(27-x)-(100-4x+6(3-x))=0

We add all the numbers together, and all the variables

2(-1x+27)-(100-4x+6(-1x+3))=0

We multiply parentheses

-2x-(100-4x+6(-1x+3))+54=0



We calculate terms in parentheses: -(100-4x+6(-1x+3)), so:

100-4x+6(-1x+3)

determiningTheFunctionDomain
-4x+6(-1x+3)+100

We multiply parentheses

-4x-6x+18+100

We add all the numbers together, and all the variables

-10x+118

Back to the equation:

-(-10x+118)



We get rid of parentheses

-2x+10x-118+54=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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