5(10-3x)=105-8x+4(11-4x)

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Solution for 5(10-3x)=105-8x+4(11-4x) equation: 



5(10-3x)=105-8x+4(11-4x)

We move all terms to the left:

5(10-3x)-(105-8x+4(11-4x))=0

We add all the numbers together, and all the variables

5(-3x+10)-(105-8x+4(-4x+11))=0

We multiply parentheses

-15x-(105-8x+4(-4x+11))+50=0



We calculate terms in parentheses: -(105-8x+4(-4x+11)), so:

105-8x+4(-4x+11)

determiningTheFunctionDomain
-8x+4(-4x+11)+105

We multiply parentheses

-8x-16x+44+105

We add all the numbers together, and all the variables

-24x+149

Back to the equation:

-(-24x+149)



We get rid of parentheses

-15x+24x-149+50=0

We add all the numbers together, and all the variables

9x-99=0

We move all terms containing x to the left, all other terms to the right

9x=99

x=99/9

x=11

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