5(x+4)=3(2x-4)+7

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Solution for 5(x+4)=3(2x-4)+7 equation: 



5(x+4)=3(2x-4)+7

We move all terms to the left:

5(x+4)-(3(2x-4)+7)=0

We multiply parentheses

5x-(3(2x-4)+7)+20=0



We calculate terms in parentheses: -(3(2x-4)+7), so:

3(2x-4)+7

We multiply parentheses

6x-12+7

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We get rid of parentheses

5x-6x+5+20=0

We add all the numbers together, and all the variables

-1x+25=0

We move all terms containing x to the left, all other terms to the right

-x=-25

x=-25/-1

x=+25

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