3y+1=7(y-1)+2

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Solution for 3y+1=7(y-1)+2 equation: 



3y+1=7(y-1)+2

We move all terms to the left:

3y+1-(7(y-1)+2)=0



We calculate terms in parentheses: -(7(y-1)+2), so:

7(y-1)+2

We multiply parentheses

7y-7+2

We add all the numbers together, and all the variables

7y-5

Back to the equation:

-(7y-5)



We get rid of parentheses

3y-7y+5+1=0

We add all the numbers together, and all the variables

-4y+6=0

We move all terms containing y to the left, all other terms to the right

-4y=-6

y=-6/-4

y=1+1/2

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