3(2x-5)=35-(4x-20)

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Solution for 3(2x-5)=35-(4x-20) equation: 



3(2x-5)=35-(4x-20)

We move all terms to the left:

3(2x-5)-(35-(4x-20))=0

We multiply parentheses

6x-(35-(4x-20))-15=0



We calculate terms in parentheses: -(35-(4x-20)), so:

35-(4x-20)

determiningTheFunctionDomain
-(4x-20)+35

We get rid of parentheses

-4x+20+35

We add all the numbers together, and all the variables

-4x+55

Back to the equation:

-(-4x+55)



We get rid of parentheses

6x+4x-55-15=0

We add all the numbers together, and all the variables

10x-70=0

We move all terms containing x to the left, all other terms to the right

10x=70

x=70/10

x=7

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