3-(b-1)-5b=2(b-3)+10

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Solution for 3-(b-1)-5b=2(b-3)+10 equation: 



3-(b-1)-5b=2(b-3)+10

We move all terms to the left:

3-(b-1)-5b-(2(b-3)+10)=0

We add all the numbers together, and all the variables

-5b-(b-1)-(2(b-3)+10)+3=0

We get rid of parentheses

-5b-b-(2(b-3)+10)+1+3=0



We calculate terms in parentheses: -(2(b-3)+10), so:

2(b-3)+10

We multiply parentheses

2b-6+10

We add all the numbers together, and all the variables

2b+4

Back to the equation:

-(2b+4)



We add all the numbers together, and all the variables

-6b-(2b+4)+4=0

We get rid of parentheses

-6b-2b-4+4=0

We add all the numbers together, and all the variables

-8b=0

b=0/-8

b=0

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