5(4w-2)=8+2(w-6)+12

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Solution for 5(4w-2)=8+2(w-6)+12 equation:



5(4w-2)=8+2(w-6)+12
We move all terms to the left:
5(4w-2)-(8+2(w-6)+12)=0
We multiply parentheses
20w-(8+2(w-6)+12)-10=0
We calculate terms in parentheses: -(8+2(w-6)+12), so:
8+2(w-6)+12
determiningTheFunctionDomain 2(w-6)+8+12
We add all the numbers together, and all the variables
2(w-6)+20
We multiply parentheses
2w-12+20
We add all the numbers together, and all the variables
2w+8
Back to the equation:
-(2w+8)
We get rid of parentheses
20w-2w-8-10=0
We add all the numbers together, and all the variables
18w-18=0
We move all terms containing w to the left, all other terms to the right
18w=18
w=18/18
w=1

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