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8(2x+3x^2)=-4x+124
We move all terms to the left:
8(2x+3x^2)-(-4x+124)=0
We multiply parentheses
24x^2+16x-(-4x+124)=0
We get rid of parentheses
24x^2+16x+4x-124=0
We add all the numbers together, and all the variables
24x^2+20x-124=0
a = 24; b = 20; c = -124;
Δ = b2-4ac
Δ = 202-4·24·(-124)
Δ = 12304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12304}=\sqrt{16*769}=\sqrt{16}*\sqrt{769}=4\sqrt{769}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{769}}{2*24}=\frac{-20-4\sqrt{769}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{769}}{2*24}=\frac{-20+4\sqrt{769}}{48} $
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