4(x-3)=2x+20

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Solution for 4(x-3)=2x+20 equation: 



4(x-3)=2x+20

We move all terms to the left:

4(x-3)-(2x+20)=0

We multiply parentheses

4x-(2x+20)-12=0

We get rid of parentheses

4x-2x-20-12=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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