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50+2/7x=x
We move all terms to the left:
50+2/7x-(x)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
-1x+2/7x+50=0
We multiply all the terms by the denominator
-1x*7x+50*7x+2=0
Wy multiply elements
-7x^2+350x+2=0
a = -7; b = 350; c = +2;
Δ = b2-4ac
Δ = 3502-4·(-7)·2
Δ = 122556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{122556}=\sqrt{4*30639}=\sqrt{4}*\sqrt{30639}=2\sqrt{30639}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-2\sqrt{30639}}{2*-7}=\frac{-350-2\sqrt{30639}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+2\sqrt{30639}}{2*-7}=\frac{-350+2\sqrt{30639}}{-14} $
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