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4x^2+20=18+35x
We move all terms to the left:
4x^2+20-(18+35x)=0
We add all the numbers together, and all the variables
4x^2-(35x+18)+20=0
We get rid of parentheses
4x^2-35x-18+20=0
We add all the numbers together, and all the variables
4x^2-35x+2=0
a = 4; b = -35; c = +2;
Δ = b2-4ac
Δ = -352-4·4·2
Δ = 1193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1193}}{2*4}=\frac{35-\sqrt{1193}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1193}}{2*4}=\frac{35+\sqrt{1193}}{8} $
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