4x2+20=18

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Solution for 4x2+20=18 equation: 



4x^2+20=18

We move all terms to the left:

4x^2+20-(18)=0

We add all the numbers together, and all the variables

4x^2+2=0

a = 4; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·4·2
Δ = -32
Delta is less than zero, so there is no solution for the equation

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