5x2-36x+5=0

Solution for 5x2-36x+5=0 equation:

5x^2-36x+5=0

a = 5; b = -36; c = +5;
Δ = b2-4ac
Δ = -362-4·5·5
Δ = 1196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1196}=\sqrt{4*299}=\sqrt{4}*\sqrt{299}=2\sqrt{299}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-2\sqrt{299}}{2*5}=\frac{36-2\sqrt{299}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+2\sqrt{299}}{2*5}=\frac{36+2\sqrt{299}}{10}
$