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3x+3/5x=18
We move all terms to the left:
3x+3/5x-(18)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
3x*5x-18*5x+3=0
Wy multiply elements
15x^2-90x+3=0
a = 15; b = -90; c = +3;
Δ = b2-4ac
Δ = -902-4·15·3
Δ = 7920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7920}=\sqrt{144*55}=\sqrt{144}*\sqrt{55}=12\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-12\sqrt{55}}{2*15}=\frac{90-12\sqrt{55}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+12\sqrt{55}}{2*15}=\frac{90+12\sqrt{55}}{30} $
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