4n-9=2(5+2n)n=

Solution for 4n-9=2(5+2n)n= equation:

4n-9=2(5+2n)n=

We move all terms to the left:

4n-9-(2(5+2n)n)=0

We add all the numbers together, and all the variables

4n-(2(2n+5)n)-9=0


We calculate terms in parentheses: -(2(2n+5)n), so:

2(2n+5)n

We multiply parentheses

4n^2+10n

Back to the equation:

-(4n^2+10n)


We get rid of parentheses

-4n^2+4n-10n-9=0

We add all the numbers together, and all the variables

-4n^2-6n-9=0

a = -4; b = -6; c = -9;
Δ = b2-4ac
Δ = -62-4·(-4)·(-9)
Δ = -108
Delta is less than zero, so there is no solution for the equation