4(x-3)+2x+6=7(x-2)+3(x-1)

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Solution for 4(x-3)+2x+6=7(x-2)+3(x-1) equation: 



4(x-3)+2x+6=7(x-2)+3(x-1)

We move all terms to the left:

4(x-3)+2x+6-(7(x-2)+3(x-1))=0

We add all the numbers together, and all the variables

2x+4(x-3)-(7(x-2)+3(x-1))+6=0

We multiply parentheses

2x+4x-(7(x-2)+3(x-1))-12+6=0



We calculate terms in parentheses: -(7(x-2)+3(x-1)), so:

7(x-2)+3(x-1)

We multiply parentheses

7x+3x-14-3

We add all the numbers together, and all the variables

10x-17

Back to the equation:

-(10x-17)



We add all the numbers together, and all the variables

6x-(10x-17)-6=0

We get rid of parentheses

6x-10x+17-6=0

We add all the numbers together, and all the variables

-4x+11=0

We move all terms containing x to the left, all other terms to the right

-4x=-11

x=-11/-4

x=2+3/4

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