10(3x-2)=100-10x

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Solution for 10(3x-2)=100-10x equation: 



10(3x-2)=100-10x

We move all terms to the left:

10(3x-2)-(100-10x)=0

We add all the numbers together, and all the variables

10(3x-2)-(-10x+100)=0

We multiply parentheses

30x-(-10x+100)-20=0

We get rid of parentheses

30x+10x-100-20=0

We add all the numbers together, and all the variables

40x-120=0

We move all terms containing x to the left, all other terms to the right

40x=120

x=120/40

x=3

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